A turtle and rabbit are in a race to see who is the first to reach a point 100 feet away. The turtle

We know the distance formula is:d = rt For the turtle, he has a rate (r) of 20 feet / minute and distance (d) of 100. We want to solve for time:Using our distance rate time calculator solving for t, we get:t = 5

A turtle and rabbit are in a race to see who is the first to reach a point 100 feet away. The turtle travels at a constant speed of 20 feet per minute for the entire 100 feet. The rabbit travels at a constant speed of 40 feet per minute for the first 50 feet, stops for 3 minutes, and then continuous at a constant speed of 40 feet per minute for the last 50 feet.
(i) Determine which animal won the race.
(ii). By how much time the animal won the race.
(iii) Explain one life lesson from the race.

We know the distance formula is:
d = rt

For the turtle, he has a rate (r) of 20 feet / minute and distance (d) of 100. We want to solve for time:
Using our distance rate time calculator solving for t, we get:
t = 5

The rabbit has 3 parts of the race:

Rabbit Part 1: Distance (d) = 50 and rate (r) = 40
Using our distance rate time calculator solving for t, we get:
t = 1.25

Rabbit Part 2: The rabbit stops for 3 minutes (t = 3)

Rabbit Part 3: Distance (d) = 50 and rate (r) = 40
Using our distance rate time calculator solving for t, we get:
t = 1.25

Total time for the rabbit from the 3 parts is (t) = 1.25 + 3 + 1.25
Total time for the rabbit from the 3 parts is (t) = 5.5

  • (i) The turtle won the race because he took more time to finish and they both started at the same time
  • (ii) We subtract the turtles time from the rabbit's time: 5.5 - 5 = 0.5 minutes which is also 30 seconds
  • (iii) Slow and Steady wins the race

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